Subarray Divisibility Solution | CSES Problem | Number of subarray divisible by k

 

Subarray Divisibility

Given an array of n integers, your task is to count the number of subarrays where the sum of values is divisible by n.

Input

The first input line has an integer n: the size of the array.

The next line has n integers a1,a2,,an: the contents of the array.

Output

Print one integer: the required number of subarrays.

Constraints
  • 1n2105
  • 109ai109
Example

Input:
5
3 1 2 7 4


Output:
1
void solve() {
// mii is map<int,int> and int is defined as long long int
int n;
cin>>n;
int sum=0;
int ans=0;
mii m;
m[0]=1;
for (int i = 0; i < n; i++)
{
int x;
cin>>x;
sum+=x;
int rem=sum%n;
if(rem<0)rem+=n;
ans+=m[rem];
m[rem]++;
}
cout<<ans<<endl;
}

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